50=16t^2+50

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Solution for 50=16t^2+50 equation: 



50=16t^2+50

We move all terms to the left:

50-(16t^2+50)=0

We get rid of parentheses

-16t^2-50+50=0

We add all the numbers together, and all the variables

-16t^2=0

a = -16; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-16)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{-32}=0$

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